Источник / закреплённая редакция

The Chain Rule

Источник пакета openstax.calculus_derivatives · OpenStax Calculus, ch. 3 Derivatives, module m53581

work
urn:openstax:clir:calculus-derivatives#M53581
номер
OpenStax Calculus, ch. 3 Derivatives, module m53581
вид
urn:openstax:clir:calculus-derivatives#treatise

m53581/index.cnxml at commit 8dbc2ce (main, 2026-07-15)

edition
urn:openstax:clir:calculus-derivatives#M53581_MAIN
язык
en
официальность
official
материализация
PINNED_OFFICIAL_BYTES
жизненный цикл
adopted: 2026-07-15

Публикации

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module/m53581#fs-id1169739194586 · section · на него ссылаются: 1

en · official · sha256:cb428baef820847d90888ef3c2a814356c3c957cfa1a6758911973df198afb2dEN

<note id="fs-id1169739194586"> <title>Rule: The Chain Rule</title> <para id="fs-id1169736612521">Let <m:math><m:mi>f</m:mi></m:math> and <m:math><m:mi>g</m:mi></m:math> be functions. For all <emphasis effect="italics">x</emphasis> in the domain of <m:math><m:mi>g</m:mi></m:math> for which <m:math><m:mi>g</m:mi></m:math> is differentiable at <emphasis effect="italics">x</emphasis> and <m:math><m:mi>f</m:mi></m:math> is differentiable at <m:math><m:mrow><m:mi>g</m:mi><m:mrow><m:mo>(</m:mo><m:mi>x</m:mi><m:mo>)</m:mo></m:mrow><m:mo>,</m:mo></m:mrow></m:math> the derivative of the composite function</para> <equation id="fs-id1169739233799" class="unnumbered"><label/><m:math><m:mrow><m:mi>h</m:mi><m:mrow><m:mo>(</m:mo><m:mi>x</m:mi><m:mo>)</m:mo></m:mrow><m:mo>=</m:mo><m:mrow><m:mo>(</m:mo><m:mrow><m:mi>f</m:mi><m:mo>∘</m:mo><m:mi>g</m:mi></m:mrow><m:mo>)</m:mo></m:mrow><m:mo stretchy="false">(</m:mo><m:mi>x</m:mi><m:mo stretchy="false">)</m:mo><m:mo>=</m:mo><m:mi>f</m:mi><m:mrow><m:mo>(</m:mo><m:mrow><m:mi>g</m:mi><m:mrow><m:mo>(</m:mo><m:mi>x</m:mi><m:mo>)</m:mo></m:mrow></m:mrow><m:mo>)</m:mo></m:mrow></m:mrow></m:math></equation> <para id="fs-id1169738949353">is given by</para> <equation id="fs-id1169738948938"><m:math><m:mrow><m:msup><m:mi>h</m:mi><m:mo>′</m:mo></m:msup><m:mrow><m:mo>(</m:mo><m:mi>x</m:mi><m:mo>)</m:mo></m:mrow><m:mo>=</m:mo><m:msup><m:mi>f</m:mi><m:mo>′</m:mo></m:msup><m:mrow><m:mo>(</m:mo><m:mrow><m:mi>g</m:mi><m:mrow><m:mo>(</m:mo><m:mi>x</m:mi><m:mo>)</m:mo></m:mrow></m:mrow><m:mo>)</m:mo></m:mrow><m:msup><m:mi>g</m:mi><m:mo>′</m:mo></m:msup><m:mrow><m:mo>(</m:mo><m:mi>x</m:mi><m:mo>)</m:mo></m:mrow><m:mo>.</m:mo></m:mrow></m:math></equation> <para id="fs-id1169739199751">Alternatively, if <m:math><m:mi>y</m:mi></m:math> is a function of <m:math><m:mrow><m:mi>u</m:mi><m:mo>,</m:mo></m:mrow></m:math> and <m:math><m:mi>u</m:mi></m:math> is a function of <m:math><m:mrow><m:mi>x</m:mi><m:mo>,</m:mo></m:mrow></m:math> then</para> <equation id="fs-id1169739187558" class="unnumbered"><label/><m:math><m:mrow><m:mfrac><m:mrow><m:mi>d</m:mi><m:mi>y</m:mi></m:mrow><m:mrow><m:mi>d</m:mi><m:mi>x</m:mi></m:mrow></m:mfrac><m:mo>=</m:mo><m:mfrac><m:mrow><m:mi>d</m:mi><m:mi>y</m:mi></m:mrow><m:mrow><m:mi>d</m:mi><m:mi>u</m:mi></m:mrow></m:mfrac><m:mo>·</m:mo><m:mfrac><m:mrow><m:mi>d</m:mi><m:mi>u</m:mi></m:mrow><m:mrow><m:mi>d</m:mi><m:mi>x</m:mi></m:mrow></m:mfrac><m:mo>.</m:mo></m:mrow></m:math></equation> </note>

Ссылаются нормы: ChainRuleJustifies

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